{"id":257,"date":"2017-10-30T12:33:49","date_gmt":"2017-10-30T12:33:49","guid":{"rendered":"http:\/\/chemdictionary.org\/?p=257"},"modified":"2017-11-14T12:24:36","modified_gmt":"2017-11-14T12:24:36","slug":"oxidation-state","status":"publish","type":"post","link":"https:\/\/chemdictionary.org\/oxidation-state\/","title":{"rendered":"Oxidation State"},"content":{"rendered":"<h2>Oxidation State Definition<\/h2>\n<p>Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. It represents the number of electrons an atom gains or losses when bonded with other atom in a molecule. As for example the oxidation number of chromium in CrCl3 is +3.<\/p>\n<h2>Rules to calculate oxidation number<\/h2>\n<p>Oxidation number is the number of electrons an atom gains or losses to form that compound. There are rules to calculate oxidation number. When any\u00a0atom has different oxidation number than expected, we can calculate that by looking how much charge is needed to achieve zero for neutral atom or charge on ion for ions, after sum up the charge on other atoms.<\/p>\n<p>To calculate oxidation number we always follow the following rules:<\/p>\n<ul>\n<li>The sum of the oxidation number of the neutral compound is zero. e.g. the sum of the oxidation number of NaCl is zero. Here the oxidation number of sodium is +1 and chlorine is -1.<\/li>\n<li>The sum of the oxidation number of an ion is equal to the charge on ion. e.g. the sum of the oxidation number of Cr<sub>2<\/sub>O<sub>7<\/sub><sup>2-\u00a0<\/sup>is -2. Here the oxidation number of oxygen is -2. Thus the oxidation number of chromium can be calculated as:<\/li>\n<\/ul>\n<p style=\"text-align: center;\">[(<span style=\"color: #ff00ff;\">oxidation number of chromium<\/span>) X (number of chromium atom)] + [(<span style=\"color: #3366ff;\">oxidation number of oxygen<\/span>) X (number of oxygen atom)] = -2<\/p>\n<p style=\"text-align: center;\">\u21d2 [(<span style=\"color: #ff00ff;\">oxidation number of chromium<\/span>) X 2] + [(<span style=\"color: #3366ff;\">-2<\/span>) X 7] = -2<\/p>\n<p style=\"text-align: center;\">\u21d2 <span style=\"color: #ff00ff;\">oxidation number of chromium<\/span> = (-2+14)\u00a0\u00f7 2 = <span style=\"color: #ff00ff;\">6<\/span><\/p>\n<ul>\n<li style=\"text-align: left;\">The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element. e.g. the oxidation number of atoms in Al and N<sub>2\u00a0<\/sub>is 0.<\/li>\n<li style=\"text-align: left;\">Oxidation number of Group I metals are +1 and and Group II metals are +2. e.g. the oxidation number of magnesium in MgCl<sub>2<\/sub> is +2 which is group II element and chlorine is -1. And sum of the oxidation number is zero.<\/li>\n<li style=\"text-align: left;\">The oxidation state of hydrogen is normally +1 but when it is bonded with metal the oxidation number is -1. e.g. in NaH and LiH, the oxidation number of hydrogen is -1.<\/li>\n<li style=\"text-align: left;\">Generally the oxidation state of oxygen is -2. But compounds like H<sub>2<\/sub>O<sub>2<\/sub>\u00a0and Na<sub>2<\/sub>O<sub>2<\/sub>, oxidation number of oxygen is -1.<\/li>\n<li style=\"text-align: left;\">The oxidation number of fluorine is always -1 but the oxidation number of chlorine differs in different compounds.<\/li>\n<\/ul>\n<h2>Oxidation Reduction reaction in terms of oxidation number<\/h2>\n<p>Oxidation and reduction reaction can be defined, depending on increase or decrease of oxidation number:<\/p>\n<ul>\n<li>Oxidation is an increase of oxidation number.<\/li>\n<li>Reduction is a decrease of oxidation number.<\/li>\n<\/ul>\n<p>As for example a reaction between cupper(II) oxide and magnesium is an oxidation reduction reaction. Here the oxidation number of Magnesium increases from 0 to +2. So this is an oxidation process. On other hand Cupper(II) ion reduced to Cupper. The oxidation number decreases from +2 to 0.<br \/>\n<img loading=\"lazy\" class=\"size-medium wp-image-17 aligncenter\" src=\"https:\/\/chemdictionary.org\/wp-content\/uploads\/2017\/10\/oxidation-4-300x267.png\" alt=\"\" width=\"300\" height=\"267\" srcset=\"https:\/\/chemdictionary.org\/wp-content\/uploads\/2017\/10\/oxidation-4-300x267.png 300w, https:\/\/chemdictionary.org\/wp-content\/uploads\/2017\/10\/oxidation-4.png 328w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<h2>Examples<\/h2>\n<ol>\n<li>Find the oxidation number of sulphur in Na<sub>2<\/sub>SO<sub>4<\/sub>.<\/li>\n<\/ol>\n<p style=\"text-align: center;\">[(oxidation number of sulfur) X (number of sulfur atom)] + [(oxidation number of sodium) X (number of sodium atom)] +\u00a0[(oxidation number of oxygen) X (number of oxygen atom)] = -1<\/p>\n<p style=\"text-align: center;\">\u21d2 [(oxidation number of sulfur) X 1] + [(+1) X 2]\u00a0+ [(-2) X 4] = 0<\/p>\n<p style=\"text-align: center;\">\u21d2 oxidation number of sulfur = (0+6)\u00a0\u00f7 1 = +6<\/p>\n<p style=\"text-align: left;\">2. Find the oxidation number of bromine in BrO<sub>4<\/sub><sup>&#8211;<\/sup><span style=\"font-size: 13.3333px;\">.<\/span><\/p>\n<p style=\"text-align: center;\">[(oxidation number of bromine) X (number of bromine atom)] +<\/p>\n<p style=\"text-align: center;\">[(oxidation number of oxygen) X (number of oxygen atom)] = -1<\/p>\n<p style=\"text-align: center;\">\u21d2 [(oxidation number of bromine) X 1] + [(-2) X 4] = -1<\/p>\n<p style=\"text-align: center;\">\u21d2 oxidation number of bromine = (-1+8)\u00a0\u00f7 1 = +7<\/p>\n<h2>Summary<\/h2>\n<ul>\n<li>Oxidation number of an atom is the charge that atom would have if the compound is composed of ions.<\/li>\n<li>When any\u00a0atom has different oxidation number than expected, we can calculate that by looking how much charge is needed to achieve zero for neutral atom or charge on ion for ions, after sum up the charge on other atoms.<\/li>\n<li>Oxidation is an increase of oxidation number.<\/li>\n<li>Reduction is a decrease of oxidation number.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Oxidation State Definition Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. It represents the number of electrons an atom gains or losses when bonded with other atom in a molecule. As for example the oxidation number of chromium in CrCl3 is +3. Rules to &#8230; <a title=\"Oxidation State\" class=\"read-more\" href=\"https:\/\/chemdictionary.org\/oxidation-state\/\" aria-label=\"More on Oxidation State\">Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"rating_form_position":"","rating_results_position":"","mr_structured_data_type":""},"categories":[17],"tags":[15],"multi-rating":{"mr_rating_results":[{"adjusted_star_result":4.82,"star_result":4.82,"total_max_option_value":5,"adjusted_score_result":4.82,"score_result":4.82,"percentage_result":96.36,"adjusted_percentage_result":96.36,"count":11,"post_id":257}]},"_links":{"self":[{"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/posts\/257"}],"collection":[{"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/comments?post=257"}],"version-history":[{"count":0,"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/posts\/257\/revisions"}],"wp:attachment":[{"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/media?parent=257"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/categories?post=257"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/chemdictionary.org\/wp-json\/wp\/v2\/tags?post=257"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}